Dissolution of of a non-volatile, non-electrolyte solute (mol. wt. = 60) in of a solvent reduces its — Solutions and Colligative Properties Chemistry Question
Question
Dissolution of $1.5\text{ g}$ of a non-volatile, non-electrolyte solute (mol. wt. = 60) in $250\text{ g}$ of a solvent reduces its freezing point by $0.1^\circ\text{C}$. Find the molal depression constant ($K_f$) of the solvent.
Answer: A
💡 Solution & Explanation
Molality $m = \frac{1.5/60}{250/1000} = \frac{0.025}{0.25} = 0.1\text{ m}$. The depression formula is $\Delta T_f = K_f \times m$. Substituting values: $0.1 = K_f \times 0.1 \implies K_f = 1.0\text{ K kg mol}^{-1}$.
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