Three gases A, B, and C have Henry's Law constants () in the order . What is the correct order of th — Solutions and Colligative Properties Chemistry Question
Question
Three gases A, B, and C have Henry's Law constants ($K_H$) in the order $K_H(A) > K_H(C) > K_H(B)$. What is the correct order of their solubility in a liquid at a given constant temperature and pressure?
Answer: B
💡 Solution & Explanation
According to Henry's Law, $P = K_H \times \chi \implies \chi = P / K_H$. At constant pressure, mole fraction (solubility) is inversely proportional to $K_H$. Therefore, the gas with the lowest $K_H$ (gas B) is the most soluble: B > C > A.
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