Solutions and Colligative PropertieshardMCQ SINGLE⭐ Must-Do

Calculate the mole fraction of glycerine () in an aqueous solution containing of water and of glycerSolutions and Colligative Properties Chemistry Question

Question

Calculate the mole fraction of glycerine ($C_3H_5(OH)_3$) in an aqueous solution containing $36\text{ g}$ of water and $46\text{ g}$ of glycerine.

Answer: B

💡 Solution & Explanation

Molar mass of water $= 18\text{ g/mol}$. Moles of water $= \frac{36}{18} = 2\text{ mol}$. Molar mass of glycerine $= 92\text{ g/mol}$. Moles of glycerine $= \frac{46}{92} = 0.5\text{ mol}$. Mole fraction of glycerine $= \frac{0.5}{2 + 0.5} = \frac{0.5}{2.5} = 0.2$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry