What is the molarity of a aqueous solution of ? — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

For salts, Normality ($N$) = Molarity ($M$) $\times$ n-factor. For $Na_2CO_3$, the total cationic charge is 2, so the n-factor = 2. $0.2 = M \times 2 \implies M = 0.1\text{ M}$.