A compound is formed by elements A and B. Atoms of A are at the corners of a cubic unit cell and B a — Solid State Chemistry Question

💡 Solution & Explanation

A atoms at $8$ corners normally contribute $8\times\frac18=1$. If one corner A atom is missing, A contribution becomes $7\times\frac18=\frac78$. B atoms at $6$ face centres contribute $6\times\frac12=3$. Ratio $A:B=\frac78:3=7:24$, so the empirical formula is $A_7B_{24}$.