A truncated octahedron, representing the Wigner-Seitz cell of a BCC lattice, features how many regul — Solid State Chemistry Question
Question
A truncated octahedron, representing the Wigner-Seitz cell of a BCC lattice, features how many regular hexagonal faces?
Answer: B
💡 Solution & Explanation
The Wigner-Seitz cell of a BCC lattice is a truncated octahedron. This solid has $14$ faces in total: $8$ regular hexagonal faces and $6$ square faces. Therefore, the number of regular hexagonal faces is $8$.
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