If is heavily doped with of , the concentration of cation vacancies created per mole is: — Solid State Chemistry Question
Question
If $NaCl$ is heavily doped with $10^{-4} \text{ mol}\%$ of $SrCl_2$, the concentration of cation vacancies created per mole is:
Answer: B
💡 Solution & Explanation
Each $Sr^{2+}$ replacing $Na^+$ creates one $Na^+$ vacancy for charge balance. $10^{-4}\text{ mol}\%$ means $10^{-6}$ mol dopant per mole of $NaCl$. Therefore vacancies per mole $=10^{-6}N_A=6.02\times10^{17}$.
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