In a normal spinel structure like , oxide ions form a CCP lattice. How are the and ions distributed? — Solid State Chemistry Question

💡 Solution & Explanation

In a normal spinel $AB_2O_4$, oxide ions form a CCP lattice. The divalent $A^{2+}$ ions occupy $1/8$ of tetrahedral voids, and the trivalent $B^{3+}$ ions occupy $1/2$ of octahedral voids. Thus in $MgAl_2O_4$, $Mg^{2+}$ occupies $1/8$ T.V. and $Al^{3+}$ occupies $1/2$ O.V.