A non-stoichiometric sample of wustite has the formula . The percentage of total iron present specif — Solid State Chemistry Question

💡 Solution & Explanation

Let the amounts of $Fe^{2+}$ and $Fe^{3+}$ be $x$ and $y$. Then $x+y=0.93$ and charge neutrality gives $2x+3y=2$. Subtracting $2(x+y)=1.86$ from this gives $y=0.14$. Percentage of iron as $Fe^{3+}$ is $\frac{0.14}{0.93}\times100\approx15\%$.