In a standard Face-Centred Cubic (FCC) structure, the shortest distance between the centers of two a — Solid State Chemistry Question
Question
In a standard Face-Centred Cubic (FCC) structure, the shortest distance between the centers of two adjacent tetrahedral voids is:
Answer: A
💡 Solution & Explanation
In an FCC unit cell, tetrahedral voids occur at positions such as $(\frac14,\frac14,\frac14)$ and $(\frac34,\frac14,\frac14)$. The separation between these adjacent tetrahedral void centers is $\frac a2$.
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