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In a standard Face-Centred Cubic (FCC) structure, the shortest distance between the centers of two aSolid State Chemistry Question

Question

In a standard Face-Centred Cubic (FCC) structure, the shortest distance between the centers of two adjacent tetrahedral voids is:

Answer: A

💡 Solution & Explanation

In an FCC unit cell, tetrahedral voids occur at positions such as $(\frac14,\frac14,\frac14)$ and $(\frac34,\frac14,\frac14)$. The separation between these adjacent tetrahedral void centers is $\frac a2$.

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