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An element crystallizes in an FCC lattice with an edge length of . If exactly of this element contaiSolid State Chemistry Question

Question

An element crystallizes in an FCC lattice with an edge length of $200 \text{ pm}$. If exactly $200 \text{ g}$ of this element contains $24 \times 10^{23}$ atoms, its density is:

Answer: A

💡 Solution & Explanation

The given sample contains $24\times10^{23}$ atoms, i.e. approximately $4$ moles, so the molar mass is $200/4=50\text{ g mol}^{-1}$. For FCC, $Z=4$. With $a=200\text{ pm}=2\times10^{-8}\text{ cm}$, $\rho=\frac{ZM}{N_Aa^3}=\frac{4\times50}{6.0\times10^{23}\times(2\times10^{-8})^3}\approx41.66\text{ g/cm}^3$.

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