Exactly mL of a solution is violently mixed with mL of a solution in a strictly acidic medium. Which — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

To determine the limiting reagent, calculate total milli-equivalents for both. Milli-equivalents of $KMnO_4 = M \times V \times n = 0.1 \times 10 \times 5 = 5.0$ meq. Milli-equivalents of $FeSO_4 = 0.1 \times 10 \times 1 = 1.0$ meq. Because $FeSO_4$ provides far fewer equivalents, it acts as the strict limiting reagent. Subtracting the reacted equivalents leaves the unreacted equivalents of $KMnO_4 = 5.0 - 1.0 = 4.0$ meq.