Redox Reactions and Volumetric AnalysishardMCQ SINGLE⭐ Must-Do

A mL sample of an aqueous solution requires exactly mL of for complete redox oxidation in an acidic Redox Reactions and Volumetric Analysis Chemistry Question

Question

A $10.0$ mL sample of an aqueous $H_2O_2$ solution requires exactly $25.0$ mL of $0.2 N$ $KMnO_4$ for complete redox oxidation in an acidic medium. What is the volume strength of the original $H_2O_2$ solution?

Answer: B

💡 Solution & Explanation

According to the Universal Law of Equivalence, milli-equivalents of $H_2O_2$ = milli-equivalents of $KMnO_4$ . Solving: $N \times 10.0 = 25.0 \times 0.2 \Rightarrow 10N = 5.0 \Rightarrow N = 0.5$ Normal. The volume strength of any $H_2O_2$ solution is directly related to its normality by the standard equation: Volume strength = $5.6 \times N$ . Therefore, Volume strength = $5.6 \times 0.5 = 2.8 V$ .

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry