As the hybridization of a Carbon atom changes sequentially from to to , its effective electronegativ — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

As the s-character increases ($sp^3$ is 25%, $sp^2$ is 33%, $sp$ is 50%), the electrons are pulled closer to the nucleus due to the high penetration of s-orbitals. This increases the effective electronegativity of the atom.