Consider the gaseous process: () and (). What is the second ionization energy () of element ? — Periodic Table and Periodicity Chemistry Question
Question
Consider the gaseous process: $X_{(g)} \rightarrow X^+_{(g)} + e^-$ ($\Delta H = 100 \text{ eV}$) and $X_{(g)} \rightarrow X^{2+}_{(g)} + 2e^-$ ($\Delta H = 250 \text{ eV}$). What is the second ionization energy ($IE_2$) of element $X$?
Answer: B
💡 Solution & Explanation
The total enthalpy change for the removal of two electrons is $IE_1 + IE_2 = 250 \text{ eV}$. Since $IE_1 = 100 \text{ eV}$, $IE_2$ must be $250 - 100 = 150 \text{ eV}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes