Determine the atomic number of the element placed exactly below an element with atomic number in the — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

$Z=34$ is Selenium (Group 16, Period 4). The next element in Group 16 is Tellurium (Period 5). Adding the magic number 18 (for period 4 to 5 transition in p-block) gives $34 + 18 = 52$.