Based on the Mulliken scale, if the first ionization energy () of an atom is and its electron affinity () is , what is its approximate electronegativity on the Pauling scale?

Question

Based on the Mulliken scale, if the first ionization energy ($IE$) of an atom is $11.2 	ext{ eV}$ and its electron affinity ($EA$) is $3.4 	ext{ eV}$, what is its approximate electronegativity on the Pauling scale?

Prashant Kotian · Accepted Answer

Correct answer: C. The Mulliken electronegativity is the average of IE and EA in eV: . To convert to the Pauling scale, divide by 2.8: .

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