What is the minimum condition required for a simple, saturated cycloalkane ring (like cyclopropane or cyclopentane) to exhibit Geometrical Isomerism?

Question

Prashant Kotian · Accepted Answer

Correct answer: C. A rigid ring prevents free rotation. For GI to be physically observed (cis/trans faces), the ring must feature at least two separately substituted carbons where the exocyclic groups differ (e.g., 1,2-dimethylcyclopropane). 1,1-dimethylcyclopropane fails this test.

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