What is the absolute minimum number of carbon atoms required for an acyclic alkane, an alkene, and a — Isomerism and Stereochemistry Chemistry Question
Question
What is the absolute minimum number of carbon atoms required for an acyclic alkane, an alkene, and an alkyne to exhibit chain isomerism, respectively?
Answer: C
💡 Solution & Explanation
To exhibit chain isomerism, the principal parent carbon chain or side chain size must differ. According to standard structural rules, the minimum number of carbon atoms required by an alkane, alkene, and alkyne to show chain isomerism is 4, 4, and 5, respectively.
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