Heating 3,3-dimethylbut-1-ene with strictly anhydrous gas yields a major substitution product. Which — Haloalkanes and Haloarenes Chemistry Question

💡 Solution & Explanation

Initial protonation forms a $2^\circ$ carbocation adjacent to a quaternary carbon. A rapid 1,2-methyl shift generates a significantly more stable $3^\circ$ carbocation, which is subsequently attacked by $Cl^-$ yielding 2-chloro-2,3-dimethylbutane.