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32. For a hypothetical cell reaction involving a one-electron transfer, the standard EMF () is measuElectrochemistry Chemistry Question

Question

32. For a hypothetical cell reaction involving a one-electron transfer, the standard EMF ($E^\circ_{cell}$) is measured to be 0.591 V at 298 K. What is the equilibrium constant ($K_{eq}$) for this reaction? (Use 2.303RT/F = 0.0591 V)

Answer: B

💡 Solution & Explanation

The relationship between standard cell potential and equilibrium constant is $E^\circ_{cell} = \frac{0.0591}{n} \log K_{eq}$. Given $E^\circ = 0.591$ V and $n=1$, we get $0.591 = 0.0591 \log K_{eq} \implies \log K_{eq} = 10 \implies K_{eq} = 10^{10}$.

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