47. An aqueous solution of Sodium Sulphate () is electrolysed using completely inert Platinum electr — Electrochemistry Chemistry Question

💡 Solution & Explanation

At the cathode, water is reduced producing $H_2$ and $OH^-$. At the anode, water is oxidised producing $O_2$ and $H^+$. Because exactly 4 equivalents of $H^+$ and $OH^-$ are generated per 4 moles of electrons, they perfectly neutralize each other in the bulk solution, leaving the pH unchanged.