ElectrochemistryhardMCQ SINGLE⭐ Must-Do

27. The standard cell potential for the reaction is 1.67 V at 298K. Calculate the standard Gibbs freElectrochemistry Chemistry Question

Question

27. The standard cell potential $E^\circ$ for the reaction $2Fe(s) + O_2(g) + 4H^+(aq) \rightarrow 2Fe^{2+}(aq) + 2H_2O(l)$ is 1.67 V at 298K. Calculate the standard Gibbs free energy change ($\Delta G^\circ$) in kJ/mol. (Use 1 F = 96500 C/mol)

Answer: B

💡 Solution & Explanation

The balanced redox reaction transfers 4 moles of electrons ($2Fe \rightarrow 2Fe^{2+} + 4e^-$), so $n=4$. $\Delta G^\circ = -nFE^\circ = -4 \times 96500 \times 1.67 = -644620$ J/mol = -644.6 kJ/mol.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry