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41. The equivalent conductance of a 0.01 N solution is 13.6 . If the limiting equivalent conductanceElectrochemistry Chemistry Question

Question

41. The equivalent conductance of a 0.01 N $NH_4OH$ solution is 13.6 $S cm^2 eq^{-1}$. If the limiting equivalent conductance ($\Lambda_{eq}^\circ$) of $NH_4OH$ is calculated to be 272 $S cm^2 eq^{-1}$, what is the exact percentage degree of dissociation ($\% \alpha$)?

Answer: B

💡 Solution & Explanation

The degree of dissociation $\alpha = \Lambda_{eq}^c / \Lambda_{eq}^\circ$. Substituting the values: $\alpha = 13.6 / 272 = 0.05$. Converting to a percentage: $0.05 \times 100\% = 5.0\%$.

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