40. At infinite dilution, the equivalent conductances of and are 91.0 and 426.2 respectively. To cal — Electrochemistry Chemistry Question
Question
40. At infinite dilution, the equivalent conductances of $CH_3COONa$ and $HCl$ are 91.0 and 426.2 $S cm^2 eq^{-1}$ respectively. To calculate $\Lambda_{eq}^\circ$ of weak $CH_3COOH$, which strong electrolyte's $\Lambda_{eq}^\circ$ is additionally required?
Answer: A
💡 Solution & Explanation
Kohlrausch's law: $\Lambda_{eq}^\circ(CH_3COOH) = \Lambda_{eq}^\circ(CH_3COONa) + \Lambda_{eq}^\circ(HCl) - \Lambda_{eq}^\circ(NaCl)$. We need to mathematically subtract out the $Na^+$ and $Cl^-$ ion contributions, which requires the infinite dilution data of $NaCl$.
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