39. The resistance of a 0.01 N solution of an electrolyte is 210 at 298 K. The cell constant is exac — Electrochemistry Chemistry Question
Question
39. The resistance of a 0.01 N solution of an electrolyte is 210 $\Omega$ at 298 K. The cell constant is exactly 0.84 $cm^{-1}$. Calculate the precise equivalent conductivity ($\Lambda_{eq}$) in $S cm^2 eq^{-1}$.
Answer: A
💡 Solution & Explanation
Specific conductance $\kappa = (\text{Cell Constant}) / R = 0.84 / 210 = 0.004 S cm^{-1}$. Equivalent conductivity $\Lambda_{eq} = (\kappa \times 1000) / N = (0.004 \times 1000) / 0.01 = 4 / 0.01 = 400 S cm^2 eq^{-1}$.
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