37. Given the limiting molar conductivities () at 298 K: = 126, = 152, and = 150 . Using Kohlrausch' — Electrochemistry Chemistry Question
Question
37. Given the limiting molar conductivities ($\Lambda_m^\circ$) at 298 K: $NaCl$ = 126, $KBr$ = 152, and $KCl$ = 150 $S cm^2 mol^{-1}$. Using Kohlrausch's law, what is the exact $\Lambda_m^\circ$ for $NaBr$?
Answer: A
💡 Solution & Explanation
By Kohlrausch's law of independent migration: $\Lambda_m^\circ(NaBr) = \Lambda_m^\circ(NaCl) + \Lambda_m^\circ(KBr) - \Lambda_m^\circ(KCl)$. Substituting the given values: $126 + 152 - 150 = 278 - 150 = 128 S cm^2 mol^{-1}$.
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