32. An aqueous solution of sodium sulphate () is electrolyzed using completely inert Platinum electr — Electrochemistry Chemistry Question

💡 Solution & Explanation

Cathode: $2H_2O + 2e^- \rightarrow H_2 + 2OH^-$ (produces base). Anode: $2H_2O \rightarrow O_2 + 4H^+ + 4e^-$ (produces acid). For every 4e- passed, 4 $OH^-$ and 4 $H^+$ are produced. When the bulk solution mixes, they neutralize perfectly to form water, leaving the net pH unchanged.