31. A technician electroplates a faucet with exactly 1.04 g of Chromium from an aqueous bath in 19.3 — Electrochemistry Chemistry Question

💡 Solution & Explanation

In $Cr_2(SO_4)_3$, Cr is $+3$. $Cr^{3+} + 3e^- \rightarrow Cr$. Moles of Cr = $1.04 / 52 = 0.02$ mol. Moles of $e^-$ required = $0.02 \times 3 = 0.06$ F. Total charge $Q = 0.06 \times 96500 = 5790 C$. Time $t = 19.3 \times 60 = 1158$ s. Current $I = Q/t = 5790 / 1158 = 5.0 A$.