29. Two electrolytic cells containing aqueous solutions of and respectively are connected in series. If exactly 1.0 mole of is deposited at the cathode of the first cell, what mass of will be deposite

Question

29. Two electrolytic cells containing aqueous solutions of $AgNO_3$ and $CuSO_4$ respectively are connected in series. If exactly 1.0 mole of $Ag$ is deposited at the cathode of the first cell, what mass of $Cu$ will be deposited in the second cell? (Atomic mass of Cu = 63.5)

Prashant Kotian · Accepted Answer

Correct answer: B. By Faraday's second law, equivalents deposited are equal. 1 mole of Ag = 1 equivalent (since takes 1e-). Therefore, exactly 1 equivalent of Cu must be deposited. For , equivalent weight = 63.5 / 2 = 31.75 g.

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