28. What is the maximum mass of sodium amalgam () formed when 500 mL of a 4.0 M aqueous solution is — Electrochemistry Chemistry Question

💡 Solution & Explanation

500 mL of 4.0 M NaCl contains 2.0 moles of $Na^+$. On a mercury cathode, the high overvoltage of $H_2$ allows $Na^+$ to discharge, forming the amalgam $NaHg$. 2.0 moles of $Na^+$ form 2.0 moles of $NaHg$. Mass = $2.0 \times (23 + 200) = 446 g$.