22. Consider the cell . The standard reduction potential of is 0.80 V. What is the approximate EMF o — Electrochemistry Chemistry Question
Question
22. Consider the cell $Pt / H_2(1 atm) / HCl(pH=3) // Ag^+(0.1 M) / Ag$. The standard reduction potential of $Ag^+/Ag$ is 0.80 V. What is the approximate EMF of the cell at 25 C?
Answer: A
💡 Solution & Explanation
Anode: $1/2 H_2 \rightarrow H^+ + e^-$. Cathode: $Ag^+ + e^- \rightarrow Ag$. $E_{cell} = E^\circ_{Ag} - E^\circ_H = 0.80 V$. Nernst: $E = 0.80 - 0.0591 \log([H^+] / [Ag^+]) = 0.80 - 0.0591 \log(10^{-3} / 10^{-1}) = 0.80 - 0.0591 \log(10^{-2}) = 0.80 - 0.0591(-2) = 0.80 + 0.1182 = 0.918 V$.
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