18. What will be the EMF of the electrode gas concentration cell at temperature T? — Electrochemistry Chemistry Question

💡 Solution & Explanation

Anode: $H_2(P_1) \rightarrow 2H^+ + 2e^-$. Cathode: $2H^+ + 2e^- \rightarrow H_2(P_2)$. Overall: $H_2(P_1) \rightarrow H_2(P_2)$. Nernst: $E = E^\circ - (RT/2F) \ln(P_2/P_1) = 0 + (RT/2F) \ln(P_1/P_2)$.