7. Given and . The standard electrode potential for is: | Electrochemistry — Chem-Mantra

Question

7. Given $E^\circ(Fe^{3+}/Fe^{2+}) = 0.77 V$ and $E^\circ(Fe^{2+}/Fe) = -0.44 V$. The standard electrode potential for $Fe^{3+} + 3e^- \rightarrow Fe$ is:

Answer: C

💡 Solution & Explanation

$dG^\circ = dG_1^\circ + dG_2^\circ$. $-3FE^\circ_3 = -1F(0.77) + (-2F(-0.44))$. $-3E^\circ_3 = -0.77 + 0.88 = 0.11$. $E^\circ_3 = -0.11 / 3 = -0.036 V$.

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