4. What is the equivalent weight of white phosphorus () in the disproportionation reaction: ? (M = m — Electrochemistry Chemistry Question
Question
4. What is the equivalent weight of white phosphorus ($P_4$) in the disproportionation reaction: $P_4 + 3OH^- + 3H_2O \rightarrow PH_3 + 3H_2PO_2^-$? (M = molar mass of $P_4$)
Answer: A
💡 Solution & Explanation
$P_4$ (0) oxidizes to $H_2PO_2^-$ (+1) with n1=4, and reduces to $PH_3$ (-3) with n2=12. The net n-factor is $(n1 \times n2)/(n1 + n2) = (4 \times 12)/16 = 3$. Equivalent weight = M/3.
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