2. In the balanced redox reaction , what are the respective integer values of x, y, and z? — Electrochemistry Chemistry Question

💡 Solution & Explanation

Oxidation half: $C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-$. Reduction half: $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$. Multiplying oxidation by 5 and reduction by 2 yields $2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O$.