19. A half cell consisting of a Pt electrode is immersed in a solution containing 1.5 M and 0.015 M — Electrochemistry Chemistry Question
Question
19. A half cell consisting of a Pt electrode is immersed in a solution containing 1.5 M $Fe^{2+}$ and 0.015 M $Fe^{3+}$. What is its reduction potential at 25 C? ($E^\circ = 0.770 V$, 2.303RT/F=0.059 V)
Answer: C
💡 Solution & Explanation
Reduction: $Fe^{3+} + e^- \rightarrow Fe^{2+}$. $E = E^\circ - 0.059 \log([Fe^{2+}] / [Fe^{3+}]) = 0.770 - 0.059 \log(1.5 / 0.015) = 0.770 - 0.059 \log(100) = 0.770 - 0.118 = 0.652 V$.
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