For the complex , compute the expected magnetic moment (spin-only) in Bohr Magnetons. — Coordination Compounds Chemistry Question

💡 Solution & Explanation

$Fe^{3+}$ is $3d^5$. $CN^-$ is a SFL. Electrons pair to form $t_{2g}^5 e_g^0$, leaving exactly 1 unpaired electron. $\mu = \sqrt{1(3)} = 1.73$ B.M. [38, 59].