What is the Crystal Field Stabilization Energy (CFSE) for a high-spin metal ion in an octahedral cry — Coordination Compounds Chemistry Question

💡 Solution & Explanation

High spin $d^4$ configuration is $t_{2g}^3 e_g^1$. $\text{CFSE} = (-0.4 \times 3 + 0.6 \times 1) \Delta_o = -1.2 + 0.6 = -0.6 \Delta_o$ [45, 46].