Based on VBT, a complex of with a coordination number of 4 is found to be paramagnetic. What is its — Coordination Compounds Chemistry Question

💡 Solution & Explanation

$Ni^{2+}$ is $d^8$. If it is paramagnetic, pairing has not occurred (requires WFL). Thus, the inner 3d orbital is not empty, forcing the use of 4s and 4p $\rightarrow sp^3$ tetrahedral [22, 33].