What is the total number of unpaired electrons calculated in and , respectively? — Coordination Compounds Chemistry Question
Question
What is the total number of unpaired electrons calculated in $[Co(NH_3)_6]^{3+}$ and $[CoF_6]^{3-}$, respectively?
Answer: C
💡 Solution & Explanation
Both have $Co^{3+}$ ($3d^6$). $NH_3$ is a SFL (pairing $\rightarrow 0$ unpaired). $F^-$ is a WFL (no pairing $\rightarrow 4$ unpaired) [42].
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