For the dissociation reaction , the degree of dissociation is small (). If the initial volume of the container is expanded by a factor of at constant temperature, by what factor does increase?

Question

For the dissociation reaction $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$, the degree of dissociation $\alpha$ is small ($\alpha \ll 1$). If the initial volume of the container is expanded by a factor of $16$ at constant temperature, by what factor does $\alpha$ increase?

Prashant Kotian · Accepted Answer

Correct answer: B. For , when is small. If the new volume , then the new degree of dissociation . Thus, it increases by a factor of 4.

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