The variation of with for a reaction is plotted as a straight line. If the line makes an angle of wi — Chemical Equilibrium Chemistry Question
Question
The variation of $\log_{10} K$ with $1/T$ for a reaction is plotted as a straight line. If the line makes an angle of $45^\circ$ with the positive x-axis (i.e., slope is +1), what is the nature of the standard enthalpy change ($\Delta H^\circ$) for the reaction?
Answer: A
💡 Solution & Explanation
The integrated Van 't Hoff equation gives slope $m = -\Delta H^\circ / (2.303 R)$. If the slope is positive ($+1$), then $-\Delta H^\circ$ must be positive, which means $\Delta H^\circ$ is negative (Exothermic reaction).
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