For the gaseous equilibrium , it is found that is exactly equal to . At what absolute temperature is — Chemical Equilibrium Chemistry Question
Question
For the gaseous equilibrium $N_2O_4(g) \rightleftharpoons 2NO_2(g)$, it is found that $K_p$ is exactly equal to $K_c$. At what absolute temperature $T$ is this condition attained? (Use $R \approx 0.0821\text{ L atm K}^{-1}\text{mol}^{-1}$)
Answer: D
💡 Solution & Explanation
The relation is $K_p = K_c(RT)^{\Delta n_g}$. For this reaction, $\Delta n_g = 2 - 1 = +1$. So, $K_p = K_c(RT)^1$. We are given $K_p = K_c$, which implies $RT = 1$. Thus, $T = 1 / R = 1 / 0.0821 \approx 12.18\text{ K}$.
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