dissociates as . When the initial pressure of is , the total pressure becomes when equilibrium is at — Chemical Equilibrium Chemistry Question
Question
$AB$ dissociates as $2AB(g) \rightleftharpoons 2A(g) + B_2(g)$. When the initial pressure of $AB$ is $500\text{ mm}$, the total pressure becomes $625\text{ mm}$ when equilibrium is attained. Calculate $K_p$.
Answer: B
💡 Solution & Explanation
Init P: $AB=500$. Eq P: $AB = 500-2x$, $A=2x$, $B_2=x$. Total $P = 500 - 2x + 2x + x = 500 + x = 625 \Rightarrow x=125$. $P_{AB} = 250$, $P_A = 250$, $P_{B_2} = 125$. $K_p = (250^2 \times 125) / (250^2) = 125$.
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