The stable enolic form of acetone () contains: — Aldehydes Ketones and Carboxylic Acids Chemistry Question
Question
The stable enolic form of acetone ($CH_3-C(OH)=CH_2$) contains:
Answer: A
💡 Solution & Explanation
The enol form ($CH_2=C(OH)CH_3$) contains 9 sigma bonds (3 in $CH_3$, 2 in $CH_2$, 1 $C=C$, 1 $C-O$, 1 $O-H$, 1 $C-C$), 1 pi bond ($C=C$), and 2 lone pairs on the oxygen atom.
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