Thermodynamics and ThermochemistrymediumMCQ SINGLE⭐ Must-Do

One mole of an ideal diatomic gas () goes from an initial state at 25°C and 1 L to a final state at Thermodynamics and Thermochemistry Chemistry Question

Question

One mole of an ideal diatomic gas ($C_v = 5 \text{ cal K}^{-1}\text{mol}^{-1}$) goes from an initial state at 25°C and 1 L to a final state at 100°C and 10 L. What is the total entropy change for this process? ($R = 2 \text{ cal K}^{-1}\text{mol}^{-1}$)

Answer: A

💡 Solution & Explanation

The general entropy change formula for an ideal gas is $\Delta S = nC_v \ln(T_2/T_1) + nR \ln(V_2/V_1)$. Substituting parameters: $T_1 = 298 \text{ K}$, $T_2 = 373 \text{ K}$, $V_1 = 1 \text{ L}$, $V_2 = 10 \text{ L}$, $n = 1$. Thus, $\Delta S = 5 \ln(373/298) + 2 \ln(10/1)$.

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