By applying Hess's Law to phase transitions, the enthalpy of sublimation () of a solid is mathematic β Thermodynamics and Thermochemistry Chemistry Question
Question
By applying Hess's Law to phase transitions, the enthalpy of sublimation ($\Delta_{sub} H$) of a solid is mathematically equal to which of the following?
Answer: B
π‘ Solution & Explanation
Sublimation is the direct transition from solid to gas. Thermodynamically, this is equivalent to first melting the solid to a liquid (Fusion) and then boiling the liquid to a gas (Vaporization). Thus, $\Delta_{sub} H = \Delta_{fus} H + \Delta_{vap} H$.
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