When of acetic acid is shaken vigorously with of activated carbon, the final equilibrium concentrati — Surface Chemistry Chemistry Question

💡 Solution & Explanation

Initial moles $= 0.6 \times 0.1 = 0.06\text{ mol}$. Final moles $= 0.5 \times 0.1 = 0.05\text{ mol}$. Moles adsorbed $= 0.01\text{ mol}$. Mass adsorbed $= 0.01 \times 60\text{ g/mol} = 0.6\text{ g} = 600\text{ mg}$. Mass adsorbed per gram of carbon $= 600\text{ mg} / 2\text{ g} = 300\text{ mg}$.