The exact numerical ratio between the root mean square speed of gas at and that of gas at is: — States of Matter and Gaseous State Chemistry Question
Question
The exact numerical ratio between the root mean square speed of $H_2$ gas at $50\text{ K}$ and that of $O_2$ gas at $800\text{ K}$ is:
Answer: C
💡 Solution & Explanation
$U_{rms} = \sqrt{3RT/M}$. For $H_2$: $\sqrt{3R(50)/2} = \sqrt{75R}$. For $O_2$: $\sqrt{3R(800)/32} = \sqrt{75R}$. The ratio is $\sqrt{75R} / \sqrt{75R} = 1$.
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